0.52x^2+250x-60=0

Solution for 0.52x^2+250x-60=0 equation:

0.52x^2+250x-60=0

a = 0.52; b = 250; c = -60;
Δ = b2-4ac
Δ = 2502-4·0.52·(-60)
Δ = 62624.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(250)-\sqrt{62624.8}}{2*0.52}=\frac{-250-\sqrt{62624.8}}{1.04}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(250)+\sqrt{62624.8}}{2*0.52}=\frac{-250+\sqrt{62624.8}}{1.04}
$